x^2-12x+41=0

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Solution for x^2-12x+41=0 equation:


Simplifying
x2 + -12x + 41 = 0

Reorder the terms:
41 + -12x + x2 = 0

Solving
41 + -12x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-41' to each side of the equation.
41 + -12x + -41 + x2 = 0 + -41

Reorder the terms:
41 + -41 + -12x + x2 = 0 + -41

Combine like terms: 41 + -41 = 0
0 + -12x + x2 = 0 + -41
-12x + x2 = 0 + -41

Combine like terms: 0 + -41 = -41
-12x + x2 = -41

The x term is -12x.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12x + 36 + x2 = -41 + 36

Reorder the terms:
36 + -12x + x2 = -41 + 36

Combine like terms: -41 + 36 = -5
36 + -12x + x2 = -5

Factor a perfect square on the left side:
(x + -6)(x + -6) = -5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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